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amy_vaulhausen

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Posts posted by amy_vaulhausen


  1. I'm having a problem with navigating around a Gann square. Its

    especially frustrating because it seems like the solution I am after

    should be very simple and yet it is eluding me.

     

    I have found online a number of sites that say that a certain method

    will work and yet I have tried it and it clearly does not, or at least it

    does not work entirely the way its claimed.

     

    For example, this site, among many others ;

     

    http://www.sacredscience.com/ferrera/gannwheel.htm

     

    States the following (please see my continuation of my message after the below quotes ( " ) and ( .... ) ;

    ...........

     

    "Basically, if you want to move around the coordinates on the Gann

    Wheel you take the number you are interested in ( such as the all

    time High or Low price) take the square root of the number, then add

    or subtract 2 from the root and resquare the result. Example: Lets

    say that we are interested in the price 664 (which is in the vertical

    column straight up from the center). The square root is 25.768 + 2 =

    27.768^2 = 771 which is the number directly above 664 or one full

    360 degree cycle out from center. If we subtracted 2 from the root

    and re-squared the number (25.768-2= 23.768^2 = 565 ) we would

    get 565 which is directly below 664 or one full 360 degree cycle in

    towards center. Incorporating the Gann Emblem with this technique,

    allows us to calculate coordinates that are

     

    conjunct (360 = +/- 2 from the root),

    opposition (180 = +/- 1 from root #),

    trine (120= +/- .666) (240= +/- 1.333),

    square (90 = +/- .5) (270= +/- 1.5)

    sextile (60 = +/- .333) (300 = +/- 1.666).

     

    This technique is extremely useful for finding coordinate squares on

    the Gann Wheel that are making hard aspects to a previous position

    on the wheel. Also, Gann believed that the numbers that connected

    the square base of the pyramid (the 4 corners of the square, i.e.

    corner #’s.) to the “gravity center” and also the numbers that ran

    straight vertical and horizontal from the “gravity center” in the form

    of a cross (cardinal numbers) were very important in balancing “Price

    & Time” on the wheel."

    ..............

     

    So I tried all of the above, and the only part that worked was the

    first one, the conjunct ;

     

    conjunct (360 = +/- 2 from the root),

     

    None of the others worked at all, and certainly not with consistency.

     

    See attached graphic.

     

    Basically what I want to do, is described in Figures (A,B,C) of the

    graphic.

     

    Regardless of the number placed in the center of the square grid, Id

    like to be able to go to any given square in a given grid and then

    from that grid cell be able to orient in any angular direction outwards

    and to any nth square.

     

    I can do this easily enough for the conjunct, for example, note the

    green arrows in figures A,B,C

     

    All I have to do is change ;

     

    conjunct (360 = +/- 2 from the root),

     

    to

     

    conjunct (360 = +/- 4,6,8,16,32 from the root), to get the next cell

    in any nth square vertically up or down

     

    However if I want to find any value outwards on angles of 45, 90,

    180, 30, 60, 120

     

    Note the the orange and red arrows for example

     

    I cant get accurate or even close values consistently to be derived.

     

    There must be some way to find out for instance, using the Gann

    Square, what the first, second, third, etc... order of value is at say

    60 degrees outward from any value placed in the center grid

     

    There must also be some way to select any given cell coordinate on

    the grid, and then from that cell, from any angle outwards find out

    what the first, second, third, value is for any nth square radiating

    outward from that point would be.

     

    Can someone help me with this? I've looked everywhere and it must

    be a simple solution?

    gannproblem.thumb.JPG.eaecdf1d1e094a3459e730bd077bdc43.JPG

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